|3+5/x |>= 8

Lösung

3 + \frac{5}{x} \geq 8

- \frac{5}{11} \leq x < 0 or 0 < x \leq 1

Intervall-Notation

[- \frac{5}{11}, 0) \cup (0, 1]

Dezimale

- 0.45454 \dots \leq x < 0 or 0 < x \leq 1

Schritte zur Lösung

3 + \frac{5}{x} \geq 8

Wende Absoluteregel an: Wenn

∣ u ∣ \geq a, a > 0

dann

u \leq - a

u \geq a

3 + \frac{5}{x} \leq - 8 or 3 + \frac{5}{x} \geq 8

3 + \frac{5}{x} \leq - 8 or 3 + \frac{5}{x} \geq 8

- \frac{5}{11} \leq x < 0 or 0 < x \leq 1

x^{2} - 7 x > 0

∣ 5 x + 3 ∣ = 18

s im pl i f y 2^{- 1} + \frac{1}{2}

∣ x - 3 ∣ = - 3

u^{2} + 3 u - 4 = 0