(1/32)^{x+2}=8^{x+1}

Lösung

(\frac{1}{32})^{x + 2} = 8^{x + 1}

x = - \frac{13}{8}

Dezimale

x = - 1.625

Schritte zur Lösung

(\frac{1}{32})^{x + 2} = 8^{x + 1}

Wende Exponentenregel an

- 5 (x + 2) = 3 (x + 1)

Löse

- 5 (x + 2) = 3 (x + 1) : x = - \frac{13}{8}

x = - \frac{13}{8}

2^{x} - 1 + 2^{x} + 2^{x} + 1 = 7

3^{2 x - 5} + 9^{x - 2} = 4

(\frac{1}{16})^{x} = (\frac{1}{8})^{6}

3^{x + 1} = 81

2^{x} + 2^{x - 1} = 48