2^x=40

Lösung

2^{x} = 40

x = \frac{ln ( 40 )}{ln ( 2 )}

Dezimale

x = 5.32192 \dots

Schritte zur Lösung

2^{x} = 40

Wende Exponentenregel an

x ln (2) = ln (40)

Löse

x ln (2) = ln (40) : x = \frac{ln ( 40 )}{ln ( 2 )}

x = \frac{ln ( 40 )}{ln ( 2 )}

so l v e f or c, p (b^{c}) = 0.7

2^{x + 3} + 2^{x + 1} = 80

- 5^{x + 1} + 8 \cdot 5^{x} = 15 \cdot 5^{- 3}

2^{x + 1} = 3^{x - 4}

5^{x} = 0.2