2^x=n

Lösung

2^{x} = n

x = \frac{ln ( n )}{ln ( 2 )}

Schritte zur Lösung

2^{x} = n

Wende Exponentenregel an

x ln (2) = ln (n)

Löse

x ln (2) = ln (n) : x = \frac{ln ( n )}{ln ( 2 )}

x = \frac{ln ( n )}{ln ( 2 )}

so l v e f or x, 8^{2 x} - 4 (8^{x}) = 3 g

9^{x + 1} + 1 = 10 (3^{x})

x^{2 x - 1} = x^{2 x - 5}

(8^{- x}) (2^{x^{2} - 2 x}) = 1

3^{1 - (2 \cdot x)} = 4^{x}