2^{n-1}=16

Lösung

2^{n - 1} = 16

n = 5

Schritte zur Lösung

2^{n - 1} = 16

Wende Exponentenregel an

n - 1 = 4

Löse

n - 1 = 4 : n = 5

n = 5

14 e^{6 - x} + e^{12 x - 7} = 0

4 = x \cdot e^{x}

e^{l n (x) \cdot 10} = a

(3 6^{4})^{x} = 6

e^{- 2 x} = 7