((32)^{0.5})^x=16

Lösung

((32)^{0.5})^{x} = 16

x = \frac{8}{5}

Dezimale

x = 1.6

Schritte zur Lösung

((32)^{0.5})^{x} = 16

Wende Exponentenregel an

2.5 x = 4

Löse

2.5 x = 4 : x = \frac{8}{5}

x = \frac{8}{5}

4^{n + 1} = 512 + 2^{2 n - 1}

2 5^{7} = 5^{x}

2^{r} = 100

3^{x + 1} = 7

2^{4} \cdot (0.5)^{- 3} = 2^{k}