3^{x+1}=4^{x-1}

Lösung

3^{x + 1} = 4^{x - 1}

x = \frac{ln ( 12 )}{2 ln ( 2 ) - ln ( 3 )}

Dezimale

x = 8.63768 \dots

Schritte zur Lösung

3^{x + 1} = 4^{x - 1}

Wende Exponentenregel an

(x + 1) ln (3) = (x - 1) ln (4)

Löse

(x + 1) ln (3) = (x - 1) ln (4) : x = \frac{ln ( 12 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 12 )}{2 ln ( 2 ) - ln ( 3 )}

2^{x} = \frac{1}{32}

2^{x} + 4^{x} = 3

2^{x} = 4^{2 x - 1}

so l v e f or y, e^{y} - p^{3} - p = 0

729 \cdot (2^{n - 5})^{n} - 64 \cdot (3^{n})^{n - 5} = 0