(b)5^{2x+1}=125

解

(b) 5^{2 x + 1} = 125

x = \frac{ln ( \frac{25}{b} )}{2 ln ( 5 )}

解答ステップ

(b) \cdot 5^{2 x + 1} = 125

以下で両辺を割る

b

5^{2 x + 1} = \frac{125}{b}

指数の規則を適用する

(2 x + 1) ln (5) = ln (\frac{125}{b})

解く

(2 x + 1) ln (5) = ln (\frac{125}{b}) : x = \frac{ln ( \frac{25}{b} )}{2 ln ( 5 )}

x = \frac{ln ( \frac{25}{b} )}{2 ln ( 5 )}