7^{x^2+2x-3}=1

Lösung

7^{x^{2} + 2 x - 3} = 1

x = 1, x = - 3

Schritte zur Lösung

7^{x^{2} + 2 x - 3} = 1

Wende Exponentenregel an

(x^{2} + 2 x - 3) ln (7) = ln (1)

Löse

(x^{2} + 2 x - 3) ln (7) = ln (1) : x = 1, x = - 3

x = 1, x = - 3

3^{x + 5} = 7^{x}

3^{2 x - 1} = 7^{x + 1}

so l v e f or n, (1 + i)^{n} = 1.42

2 = 1 0^{x}

15000 = 750 0^{3 x}