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人気のある代数 >

(3)r=(x^2=9-3=5)

解

(3) r = (x^{2} = 9 - 3 = 5)

解

x = \frac{- 0 + 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}, x = \frac{- 0 - 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}

解答ステップ

(3) r = (x^{2} = 9 - 3 = 5)

改良

3 r = (x^{2} = 9 - 3 = 5)

辺を交換する

(x^{2} = 9 - 3 = 5) = 3 r

3 r

を左側に移動します

x^{2} = 9 - 3 = 5 - 3 r = 0

標準的な形式で書く

a x^{2} + b x + c = 0

= 9 x^{2} - 3 = 5 - 3 r = 0

解くとthe二次式

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}

x = \frac{- 0 + 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}

x = \frac{- 0 - 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}

二次equationの解:

x = \frac{- 0 + 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}, x = \frac{- 0 - 0 ^{2} - 4 = 9 ( - 3 = 5 - 3 r )}{2 = 9}

グラフ

人気の例

(a-2)*x^2+(b-3)x+1=(2a-8)*x^2+(b+5)x+5

(a - 2) \cdot x^{2} + (b - 3) x + 1 = (2 a - 8) \cdot x^{2} + (b + 5) x + 5

solvefor x,13x^2+2x^2y=1

so l v e f or x, 13 x^{2} + 2 x^{2} y = 1

solvefor a,e^2+f^2=2(a^2+b^2)

so l v e f or a, e^{2} + f^{2} = 2 (a^{2} + b^{2})

solvefor x,(x^2)/3+(y^2)/3 =(a^2)/3

so l v e f or x, \frac{x ^{2}}{3} + \frac{y ^{2}}{3} = \frac{a ^{2}}{3}

solvefor x,f(x^2+x)=x+2x

so l v e f or x, f (x^{2} + x) = x + 2 x