(1.06)^{40}*0.5=x^{40}

解

(1.06)^{40} \cdot 0.5 = x^{40}

x = 40 \frac{1.28571 E 15}{2.5 E 14}, x = - 40 \frac{1.28571 E 15}{2.5 E 14}

十進法表記

x = 1.04178 \dots, x = - 1.04178 \dots

解答ステップ

(1.06)^{40} \cdot 0.5 = x^{40}

辺を交換する

x^{40} = (1.06)^{40} \cdot 0.5

簡素化

1.0 6^{40} \cdot 0.5 : 5.14285 \dots

x^{n} = f (a)

の場合, n は偶数, 解は

x = n f (a), - n f (a)

x = 40 5.14285 \dots, x = - 40 5.14285 \dots

40 5.14285 \dots = 40 \frac{1.28571 E 15}{2.5 E 14}

- 40 5.14285 \dots = - 40 \frac{1.28571 E 15}{2.5 E 14}

x = 40 \frac{1.28571 E 15}{2.5 E 14}, x = - 40 \frac{1.28571 E 15}{2.5 E 14}