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人気のある代数 >

d^4+1=0

解

d^{4} + 1 = 0

解

d = \frac{1}{2} + \frac{1}{2} i, d = - \frac{1}{2} - \frac{1}{2} i, d = \frac{1}{2} - \frac{1}{2} i, d = - \frac{1}{2} + \frac{1}{2} i

解答ステップ

d^{4} + 1 = 0

1

を右側に移動します

d^{4} = - 1

equationを

u = d^{2}

と以下で書き換える:

u^{2} = d^{4}

u^{2} = - 1

解く

u^{2} = - 1 : u = i, u = - i

u = i, u = - i

再び

u = d^{2}

に置き換えて以下を解く:

d

解く

d^{2} = i : d = \frac{1}{2} + \frac{1}{2} i, d = - \frac{1}{2} - \frac{1}{2} i

解く

d^{2} = - i : d = \frac{1}{2} - \frac{1}{2} i, d = - \frac{1}{2} + \frac{1}{2} i

解答は

d = \frac{1}{2} + \frac{1}{2} i, d = - \frac{1}{2} - \frac{1}{2} i, d = \frac{1}{2} - \frac{1}{2} i, d = - \frac{1}{2} + \frac{1}{2} i

グラフ

人気の例

(3x+2)(2x+2)(x+1)=2944

(3 x + 2) (2 x + 2) (x + 1) = 2944

x^3-3x^2+2x-6=0

x^{3} - 3 x^{2} + 2 x - 6 = 0

5x^3+3x^2-7x+8=0

5 x^{3} + 3 x^{2} - 7 x + 8 = 0

2 x^{4} - x^{2} - 6 = 0

(x^2+2x-14)^5=1

(x^{2} + 2 x - 14)^{5} = 1