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人気のある代数 >

solvefor t,s_{t}(t)(t)=f(p_{t}(t)(t)-1)

解

解く

t, s_{t} (t) (t) (t) = f (p_{t} (t) (t) (t) - 1)

解

t = i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}, t = - i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}; s_{t} (t) \neq = p_{t} (t) f

解答ステップ

s_{t} (t) (t) (t) = f (p_{t} (t) (t) (t) - 1)

f (p_{t} (t) (t) (t) - 1)

を左側に移動します

t^{2} s_{t} (t) - f (t^{2} p_{t} (t) - 1) = 0

拡張

t^{2} s_{t} (t) - f (t^{2} p_{t} (t) - 1) : s_{t} (t) t^{2} - p_{t} (t) f t^{2} + f

s_{t} (t) t^{2} - p_{t} (t) f t^{2} + f = 0

f

を右側に移動します

s_{t} (t) t^{2} - p_{t} (t) f t^{2} = - f

因数

s_{t} (t) t^{2} - p_{t} (t) f t^{2} : t^{2} (s_{t} (t) - p_{t} (t) f)

t^{2} (s_{t} (t) - p_{t} (t) f) = - f

以下で両辺を割る

s_{t} (t) - p_{t} (t) f; s_{t} (t) \neq = p_{t} (t) f

t^{2} = - \frac{f}{s _{t} ( t ) - p _{t} ( t ) f}; s_{t} (t) \neq = p_{t} (t) f

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

t = - \frac{f}{s _{t} ( t ) - p _{t} ( t ) f}, t = - - \frac{f}{s _{t} ( t ) - p _{t} ( t ) f}; s_{t} (t) \neq = p_{t} (t) f

簡素化

- \frac{f}{s _{t} ( t ) - p _{t} ( t ) f} : i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}

簡素化

- - \frac{f}{s _{t} ( t ) - p _{t} ( t ) f} : - i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}

t = i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}, t = - i \frac{f}{s _{t} ( t ) - f p _{t} ( t )}; s_{t} (t) \neq = p_{t} (t) f

グラフ

人気の例

solvefor x,-5x+3y=-60

so l v e f or x, - 5 x + 3 y = - 60

solvefor x,p^2-(x+3y)p+2y(x+y)=0

so l v e f or x, p^{2} - (x + 3 y) p + 2 y (x + y) = 0

(-11+u)/6 =-203

\frac{- 11 + u}{6} = - 203

5(x+8)+4(x-6)=61

5 (x + 8) + 4 (x - 6) = 61

3 c + 4 u = 33