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Popular >

|b+2|<= 3

Solution

∣ b + 2 ∣ \leq 3

Solution

- 5 \leq b \leq 1

+1

Solution steps

∣ b + 2 ∣ \leq 3

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 3 \leq b + 2 \leq 3

b + 2 \geq - 3 and b + 2 \leq 3

b \geq - 5 and b \leq 1

Merge Overlapping Intervals

- 5 \leq b \leq 1

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Frequently Asked Questions (FAQ)

What is |b+2|<= 3 ?
The solution to |b+2|<= 3 is -5<= b<= 1