faktorisieren x^3-11x^2+36x-36

Lösung

faktorisieren

x^{3} - 11 x^{2} + 36 x - 36

(x - 2) (x - 3) (x - 6)

Schritte zur Lösung

x^{3} - 11 x^{2} + 36 x - 36

Wende den rationalen Nullstellentest an

= (x - 2) \frac{x ^{3} - 11 x ^{2} + 36 x - 36}{x - 2}

\frac{x ^{3} - 11 x ^{2} + 36 x - 36}{x - 2} = x^{2} - 9 x + 18

= (x - 2) (x^{2} - 9 x + 18)

Faktorisiere

x^{2} - 9 x + 18 : (x - 3) (x - 6)

= (x - 2) (x - 3) (x - 6)

j o in (b) {(\frac{1}{2})^{∣} k ∣}

s im pl i f y (\frac{x - y}{3})^{3}

s im pl i f y \frac{7 + 4}{cot ( x )}

s im pl i f y \frac{12 m ^{2} n ^{2} + 16 m ^{3} n ^{3} - 20 m ^{4} n ^{2}}{4 m ^{2} n ^{2}}

f a c t or 54 x^{4} + 27 x^{3} a - 16 x - 8 a