What is 64/125*p^3-8-96/25*p^2+48/5*p ?

The solution to 64/125*p^3-8-96/25*p^2+48/5*p is (64p^3}{125}-(96p^2)/(25)+\frac{48p)/5-8

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simplify 64/125p^3-8-96/25p^2+48/5*p

simplify

\frac{64}{125} \cdot p^{3} - 8 - \frac{96}{25} \cdot p^{2} + \frac{48}{5} \cdot p

\frac{64 p ^{3}}{125} - \frac{96 p ^{2}}{25} + \frac{48 p}{5} - 8

Solution steps

\frac{64}{125} p^{3} - 8 - \frac{96}{25} p^{2} + \frac{48}{5} p

Multiply

\frac{64}{125} p^{3} : \frac{64 p ^{3}}{125}

= \frac{64 p ^{3}}{125} - 8 - \frac{96}{25} p^{2} + \frac{48}{5} p

Multiply

\frac{96}{25} p^{2} : \frac{96 p ^{2}}{25}

= \frac{64 p ^{3}}{125} - 8 - \frac{96 p ^{2}}{25} + \frac{48}{5} p

Multiply

\frac{48}{5} p : \frac{48 p}{5}

= \frac{64 p ^{3}}{125} - 8 - \frac{96 p ^{2}}{25} + \frac{48 p}{5}

Rewrite in standard form

= \frac{64 p ^{3}}{125} - \frac{96 p ^{2}}{25} + \frac{48 p}{5} - 8

f a c t or a^{10} - a^{8} + a^{6} + a^{4}

f a c t or 35 x y - 55 x^{2} + 10 x

s im pl i f y 2 x (x + 4) - 3 x (2 x - 5)

s im pl i f y (x - 1) + (12 - 7.5 x)

s im pl i f y 6 a^{2} - 5 a - 5

What is 64/125*p^3-8-96/25*p^2+48/5*p ?
The solution to 64/125*p^3-8-96/25*p^2+48/5*p is (64p^3}{125}-(96p^2)/(25)+\frac{48p)/5-8