What are the solutions to the equation x^2+15x+44=0 ?

The solutions to the equation x^2+15x+44=0 are x=-4,x=-11

Find the zeros of x^2+15x+44=0

The zeros of x^2+15x+44=0 are x=-4,x=-11

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x^{2} + 15 x + 44 = 0

x = - 4, x = - 11

Solution steps

x^{2} + 15 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 44 = 7

x_{1, 2} = \frac{- 15 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 7}{2 \cdot 1}, x_{2} = \frac{- 15 - 7}{2 \cdot 1}

x = \frac{- 15 + 7}{2 \cdot 1} : - 4

x = \frac{- 15 - 7}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 4, x = - 11

\frac{x}{3} < 4 x + 11

4 \cdot 1 0^{- 7} = 7 \cdot 1 0^{- 9} (x - 30)

\frac{2 π}{8 π}

(3 + 2 i) (2 - i) - (1 - i) (2 - 3 i)

6 (2 x - 2) = 19 (x - 12)

What are the solutions to the equation x^2+15x+44=0 ?
The solutions to the equation x^2+15x+44=0 are x=-4,x=-11
Find the zeros of x^2+15x+44=0
The zeros of x^2+15x+44=0 are x=-4,x=-11