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Frequently Asked Questions (FAQ)
What are the solutions to the equation -0.1x^2+0.1x=-0.03 ?
- The solutions to the equation -0.1x^2+0.1x=-0.03 are x=-(-5+sqrt(55))/(10),x=(5+sqrt(55))/(10)
Find the zeros of -0.1x^2+0.1x=-0.03
- The zeros of -0.1x^2+0.1x=-0.03 are x=-(-5+sqrt(55))/(10),x=(5+sqrt(55))/(10)