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What are the solutions to the equation (-2/3)^2+y^2=1 ?
The solutions to the equation (-2/3)^2+y^2=1 are y=(sqrt(5))/3 ,y=-(sqrt(5))/3Find the zeros of (-2/3)^2+y^2=1
The zeros of (-2/3)^2+y^2=1 are y=(sqrt(5))/3 ,y=-(sqrt(5))/3