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Frequently Asked Questions (FAQ)
What are the solutions to the equation (4x-7)^2=-16 ?
- The solutions to the equation (4x-7)^2=-16 are x= 7/4+i,x= 7/4-i
Find the zeros of (4x-7)^2=-16
- The zeros of (4x-7)^2=-16 are x= 7/4+i,x= 7/4-i