solvefor x,I(x)=12.5+0.02x

解答

求解

x, I (x) = 12.5 + 0.02 x

x = \frac{625}{50 I - 1}; I \neq = \frac{1}{50}

求解步骤

I (x) = 12.5 + 0.02 x

在两边乘以

100

I x \cdot 100 = 1250 + 2 x

将

2 x

para o lado esquerdo

I x \cdot 100 - 2 x = 1250

分解

I x \cdot 100 - 2 x : 2 x (50 I - 1)

2 x (50 I - 1) = 1250

两边除以

2 (50 I - 1); I \neq = \frac{1}{50}

x = \frac{625}{50 I - 1}; I \neq = \frac{1}{50}

\frac{( 2 y - 3 )}{4} = \frac{( 6 y + 7 )}{3}

\frac{x - 1}{4} + \frac{2 x + 3}{6} = x - 1

so l v e f or x, 5 x + 3 y = 11

so l v e f or x, 5 x + 3 y = 17

so l v e f or x, 5 x + 3 y = - 1