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受欢迎的代数 >

solvefor a,a+[a+d]+[a+2d]=12

解答

求解

a, a + [a + d] + [a + 2 d] = 12

解答

a = 4 - d

求解步骤

a + [a + d] + [a + 2 d] = 12

去除括号:

(a) = a

a + a + d + a + 2 d = 12

对同类项分组

a + a + a + d + 2 d = 12

同类项相加:

d + 2 d = 3 d

a + a + a + 3 d = 12

同类项相加:

a + a + a = 3 a

3 a + 3 d = 12

将

3 d

到右边

3 a = 12 - 3 d

两边除以

3

a = 4 - d

作图

流行的例子

5 z + 7 = 4

x=sqrt(1-\sqrt{1-\sqrt{1)}}

x = 1 - 1 - 1

solvefor x,x-3y-1=0

so l v e f or x, x - 3 y - 1 = 0

3t+t/5-5= 1/5+5t

3 t + \frac{t}{5} - 5 = \frac{1}{5} + 5 t

2 x + x - 5 = x + 5