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Popular >

(2n+2)!

Solution

(2 n + 2)!

Solution

(2 n + 2)! = (2 n + 2) \cdot (2 n + 1) \cdot \dots \cdot 2 \cdot 1

Solution steps

Apply factorial rule:

n! = n \cdot (n - 1) \dots \cdot 2 \cdot 1

(2 n + 2)! = (2 n + 2) \cdot (2 n + 1) \cdot \dots \cdot 2 \cdot 1

Popular Examples

simplify (-1)/3+1 simplify

\frac{- 1}{3} + 1

expand (k(k+1))/2+(k+1)expand

\frac{k ( k + 1 )}{2} + (k + 1)

2 x^{2} - 11 = 0

(2x+4)/3 = x/6-3

\frac{2 x + 4}{3} = \frac{x}{6} - 3

factor x^{16}-y^{18}factor

x^{16} - y^{18}

Frequently Asked Questions (FAQ)

What is (2n+2)! ?
The solution to (2n+2)! is (2n+2)!=(2n+2)*(2n+1)*\ldots*2*1