iz=|4-3i|-(2-i)(3+i)

Lösung

i z = ∣ 4 - 3 i ∣ - (2 - i) (3 + i)

z = 1 + 2 i

Schritte zur Lösung

i z = ∣ 4 - 3 i ∣ - (2 - i) (3 + i)

Vereinfache

∣ 4 - 3 i ∣ - (2 - i) (3 + i) : 5 - (7 - i)

i z = 5 - (7 - i)

Teile beide Seiten durch

i

z = 1 + 2 i

4 (x + 1) - 5 (x + 6) = 3 x + 2

\frac{2 x + 5}{3} + 2 x = 7

x - 1 - 4 x = 5 - 3 x - 6

x - 9 - 2 (x + 3) = - 12

x^{1} = - 2