What are the solutions to the equation 5x^2+23x-10=0 ?

The solutions to the equation 5x^2+23x-10=0 are x= 2/5 ,x=-5

Find the zeros of 5x^2+23x-10=0

The zeros of 5x^2+23x-10=0 are x= 2/5 ,x=-5

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5 x^{2} + 23 x - 10 = 0

x = \frac{2}{5}, x = - 5

Decimal Notation

x = 0.4, x = - 5

Solution steps

5 x^{2} + 23 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

2 3^{2} - 4 \cdot 5 (- 10) = 27

x_{1, 2} = \frac{- 23 \pm 27}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 23 + 27}{2 \cdot 5}, x_{2} = \frac{- 23 - 27}{2 \cdot 5}

x = \frac{- 23 + 27}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 23 - 27}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 5

(m)^{7}

7 \cdot 14

2 x^{2} - 24 x + 52 = 0

- 3 - 0.5 x + 13 = 0.3 x + 6.2

16 - x^{2} = - 19

What are the solutions to the equation 5x^2+23x-10=0 ?
The solutions to the equation 5x^2+23x-10=0 are x= 2/5 ,x=-5
Find the zeros of 5x^2+23x-10=0
The zeros of 5x^2+23x-10=0 are x= 2/5 ,x=-5