0.1x^2+0.2x-44=0

解

0.1 x^{2} + 0.2 x - 44 = 0

x = 20, x = - 22

解答ステップ

0.1 x^{2} + 0.2 x - 44 = 0

以下で両辺を乗じる:

10

x^{2} + 2 x - 440 = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 440 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 440) = 42

x_{1, 2} = \frac{- 2 \pm 42}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 2 + 42}{2 \cdot 1}, x_{2} = \frac{- 2 - 42}{2 \cdot 1}

x = \frac{- 2 + 42}{2 \cdot 1} : 20

x = \frac{- 2 - 42}{2 \cdot 1} : - 22

二次equationの解:

x = 20, x = - 22