t^2-2t-24=0

解

t^{2} - 2 t - 24 = 0

t = 6, t = - 4

解答ステップ

t^{2} - 2 t - 24 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

t_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, t_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

t = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

t = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

二次equationの解:

t = 6, t = - 4