(2k+1)x^2+7x+2=0

Lösung

(2 k + 1) x^{2} + 7 x + 2 = 0

x = \frac{- 7 + - 16 k + 41}{2 ( 2 k + 1 )}, x = \frac{- 7 - - 16 k + 41}{2 ( 2 k + 1 )}; k \neq = - \frac{1}{2}

Schritte zur Lösung

(2 k + 1) x^{2} + 7 x + 2 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( 2 k + 1 ) \cdot 2}{2 ( 2 k + 1 )}

Vereinfache

7^{2} - 4 (2 k + 1) \cdot 2 : - 16 k + 41

x_{1, 2} = \frac{- 7 \pm - 16 k + 41}{2 ( 2 k + 1 )}; k \neq = - \frac{1}{2}

Trenne die Lösungen

x_{1} = \frac{- 7 + - 16 k + 41}{2 ( 2 k + 1 )}, x_{2} = \frac{- 7 - - 16 k + 41}{2 ( 2 k + 1 )}

x = \frac{- 7 + - 16 k + 41}{2 ( 2 k + 1 )}; k \neq = - \frac{1}{2}

x = \frac{- 7 - - 16 k + 41}{2 ( 2 k + 1 )}; k \neq = - \frac{1}{2}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- 7 + - 16 k + 41}{2 ( 2 k + 1 )}, x = \frac{- 7 - - 16 k + 41}{2 ( 2 k + 1 )}; k \neq = - \frac{1}{2}

- 16 x^{2} + 80 x = 0

x^{2} - 3 x - 40 = 48

2.07 x^{2} - 3.79 x + 1.34 = 0

2 x^{2} + 1 x + 0 = 0

- 3 x^{2} + 21 x - 30 = 0