x^2+8x-945=0

解

x^{2} + 8 x - 945 = 0

x = 27, x = - 35

解答ステップ

x^{2} + 8 x - 945 = 0

解くとthe二次式

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 945 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 945) = 62

x_{1, 2} = \frac{- 8 \pm 62}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 8 + 62}{2 \cdot 1}, x_{2} = \frac{- 8 - 62}{2 \cdot 1}

x = \frac{- 8 + 62}{2 \cdot 1} : 27

x = \frac{- 8 - 62}{2 \cdot 1} : - 35

二次equationの解:

x = 27, x = - 35