What is 3/(|2x-1|)>= 4 ?

The solution to 3/(|2x-1|)>= 4 is 1/8 <= x< 1/2 \lor 1/2 <x<= 7/8

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3/(|2x-1|)>= 4

\frac{3}{∣ 2 x - 1 ∣} \geq 4

\frac{1}{8} \leq x < \frac{1}{2} or \frac{1}{2} < x \leq \frac{7}{8}

Solution steps

\frac{3}{∣ 2 x - 1 ∣} \geq 4

Find positive and negative intervals

x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

\frac{1}{8} \leq x < \frac{1}{2} or \frac{1}{2} < x \leq \frac{7}{8}

1 - \frac{8}{27} x^{3}

\frac{b}{5} = 1

y^{2} = 64

(36 x)^{\frac{1}{2}}

\frac{- 4}{7 i}

What is 3/(|2x-1|)>= 4 ?
The solution to 3/(|2x-1|)>= 4 is 1/8 <= x< 1/2 \lor 1/2 <x<= 7/8