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Frequently Asked Questions (FAQ)
What are the solutions to the equation x^2+4x+4=18 ?
- The solutions to the equation x^2+4x+4=18 are x=-2+3sqrt(2),x=-2-3sqrt(2)
Find the zeros of x^2+4x+4=18
- The zeros of x^2+4x+4=18 are x=-2+3sqrt(2),x=-2-3sqrt(2)