What is ((-3u^{-3}h^3)^5)/(12u^{-9)h^{10}} ?

The solution to ((-3u^{-3}h^3)^5)/(12u^{-9)h^{10}} is -(81h^5)/(4u^6)

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simplify ((-3u^{-3}h^3)^5)/(12u^{-9)h^{10}}

simplify

\frac{( - 3 u ^{- 3} h ^{3} ) ^{5}}{12 u ^{- 9} h ^{10}}

- \frac{81 h ^{5}}{4 u ^{6}}

Solution steps

\frac{( - 3 u ^{- 3} h ^{3} ) ^{5}}{12 u ^{- 9} h ^{10}}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3 u^{- 3} h^{3})^{5} = - (3 u^{- 3} h^{3})^{5}

= \frac{- ( 3 u ^{- 3} h ^{3} ) ^{5}}{12 u ^{- 9} h ^{10}}

Simplify

(3 u^{- 3} h^{3})^{5} : 3^{5} \cdot \frac{1}{u ^{15}} h^{15}

= \frac{- 3 ^{5} \cdot \frac{1}{u ^{15}} h ^{15}}{12 u ^{- 9} h ^{10}}

Factor the number:

12 = 3 \cdot 4

= \frac{- 3 ^{5} \cdot \frac{1}{u ^{15}} h ^{15}}{3 \cdot 4 u ^{- 9} h ^{10}}

\frac{3 ^{5}}{3} = 3^{4}

= \frac{- 3 ^{4} \cdot \frac{1}{u ^{15}} h ^{15}}{4 u ^{- 9} h ^{10}}

Simplify

\frac{h ^{15}}{h ^{10}} : h^{5}

= \frac{- 3 ^{4} \cdot \frac{1}{u ^{15}} h ^{5}}{4 u ^{- 9}}

Simplify

\frac{- 3 ^{4} \cdot \frac{1}{u ^{15}} h ^{5}}{4 u ^{- 9}} : - \frac{81 h ^{5}}{u ^{6} \cdot 4}

= - \frac{81 h ^{5}}{u ^{6} \cdot 4}

= - \frac{81 h ^{5}}{4 u ^{6}}

x + 5 > x + 4

x^{3} y^{5} + y^{2}

0.1 (5 + x) = 0.6 (x + 8)

0 = x^{2} + 3

2 n^{2} - 20 n + 50

What is ((-3u^{-3}h^3)^5)/(12u^{-9)h^{10}} ?
The solution to ((-3u^{-3}h^3)^5)/(12u^{-9)h^{10}} is -(81h^5)/(4u^6)