What is ((x+1))/(x-2)>= x/(x-1) ?

The solution to ((x+1))/(x-2)>= x/(x-1) is 1/2 2

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((x+1))/(x-2)>= x/(x-1)

\frac{( x + 1 )}{x - 2} \geq \frac{x}{x - 1}

\frac{1}{2} \leq x < 1 or x > 2

Interval Notation

[\frac{1}{2}, 1) \cup (2, \infty)

Decimal Notation

0.5 \leq x < 1 or x > 2

Solution steps

\frac{x + 1}{x - 2} \geq \frac{x}{x - 1}

Rewrite in standard form

\frac{2 x - 1}{( x - 2 ) ( x - 1 )} \geq 0

Identify the intervals

\frac{1}{2} \leq x < 1 or x > 2

25 - \frac{x}{2} = \frac{x}{3}

- 5 m < 10

3 x^{2} + 5 x y - 12 y^{2}

2 x^{2} - 9 x = 0

What is ((x+1))/(x-2)>= x/(x-1) ?
The solution to ((x+1))/(x-2)>= x/(x-1) is 1/2 <= x<1\lor x>2