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Beliebt Algebra >

faktorisieren x^4-2x^3+x^2+12x+8

Lösung

faktorisieren

x^{4} - 2 x^{3} + x^{2} + 12 x + 8

Lösung

(x + 1)^{2} (x^{2} - 4 x + 8)

Schritte zur Lösung

x^{4} - 2 x^{3} + x^{2} + 12 x + 8

Wende den rationalen Nullstellentest an

= (x + 1) \frac{x ^{4} - 2 x ^{3} + x ^{2} + 12 x + 8}{x + 1}

\frac{x ^{4} - 2 x ^{3} + x ^{2} + 12 x + 8}{x + 1} = x^{3} - 3 x^{2} + 4 x + 8

= (x + 1) (x^{3} - 3 x^{2} + 4 x + 8)

Faktorisiere

x^{3} - 3 x^{2} + 4 x + 8 : (x + 1) (x^{2} - 4 x + 8)

= (x + 1) (x + 1) (x^{2} - 4 x + 8)

Wende Exponentenregel an:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x^{2} - 4 x + 8)

Beliebte Beispiele

faktorisieren y^2+xy-2x^2

f a c t or y^{2} + x y - 2 x^{2}

-2(x+6)>= 3x-x+4

- 2 (x + 6) \geq 3 x - x + 4

16 x - 14 \leq 66

(5x-14)/(-3)=-7

\frac{5 x - 14}{- 3} = - 7

vereinfachen (1/1000)^{2/3}

s im pl i f y (\frac{1}{1000})^{\frac{2}{3}}