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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x-7=-5x^2 ?
- The solutions to the equation 4x-7=-5x^2 are x=-(2+sqrt(39))/5 ,x=(sqrt(39)-2)/5
Find the zeros of 4x-7=-5x^2
- The zeros of 4x-7=-5x^2 are x=-(2+sqrt(39))/5 ,x=(sqrt(39)-2)/5