What are the solutions to the equation 2x^2+27=-13 ?

The solutions to the equation 2x^2+27=-13 are x=2sqrt(5)i,x=-2sqrt(5)i

Find the zeros of 2x^2+27=-13

The zeros of 2x^2+27=-13 are x=2sqrt(5)i,x=-2sqrt(5)i

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2 x^{2} + 27 = - 13

x = 25 i, x = - 25 i

Solution steps

2 x^{2} + 27 = - 13

Move

27

to the right side

2 x^{2} = - 40

Divide both sides by

2

x^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 20, x = - - 20

- 20 = 25 i

- - 20 = - 25 i

x = 25 i, x = - 25 i

4 z + 3 = z - 2

3 x^{2} - 10 x - 48

1 - 2 (- \frac{3}{5})^{2}

(\frac{16}{81})^{- \frac{3}{4}}

\frac{2 y}{5} + \frac{y - 4}{2} = \frac{y + 1}{4}

What are the solutions to the equation 2x^2+27=-13 ?
The solutions to the equation 2x^2+27=-13 are x=2sqrt(5)i,x=-2sqrt(5)i
Find the zeros of 2x^2+27=-13
The zeros of 2x^2+27=-13 are x=2sqrt(5)i,x=-2sqrt(5)i