What is the answer to (3y-2)/7 =(y+6)/4 ?

The answer to (3y-2)/7 =(y+6)/4 is y=10

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(3y-2)/7 =(y+6)/4

\frac{3 y - 2}{7} = \frac{y + 6}{4}

y = 10

Solution steps

\frac{3 y - 2}{7} = \frac{y + 6}{4}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 y - 2) \cdot 4 = 7 (y + 6)

Expand

(3 y - 2) \cdot 4 : 12 y - 8

Expand

7 (y + 6) : 7 y + 42

12 y - 8 = 7 y + 42

Move

8

to the right side

12 y = 7 y + 50

Move

7 y

to the left side

5 y = 50

Divide both sides by

5

y = 10

(x - 2)^{2} - 9 \geq 0

x^{4} - x^{3} - 8 x^{2} + 12 x

\frac{3 ( 2 ^{2} c ^{4} d ^{5} ) ^{3}}{( 2 c d ^{2} ) ^{4}}

\frac{a ^{\frac{1}{3}}}{a ^{\frac{1}{4}}}

3 x - 27 = 0

What is the answer to (3y-2)/7 =(y+6)/4 ?
The answer to (3y-2)/7 =(y+6)/4 is y=10
Solve for y: (3y-2)/7 =(y+6)/4
The solution is y=10