What are the solutions to the equation 16t^2-64t-64=0 ?

The solutions to the equation 16t^2-64t-64=0 are t=2(1+sqrt(2)),t=2(1-sqrt(2))

Find the zeros of 16t^2-64t-64=0

The zeros of 16t^2-64t-64=0 are t=2(1+sqrt(2)),t=2(1-sqrt(2))

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16 t^{2} - 64 t - 64 = 0

t = 2 (1 + 2), t = 2 (1 - 2)

Decimal Notation

t = 4.82842 \dots, t = - 0.82842 \dots

Solution steps

16 t^{2} - 64 t - 64 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 64 ) \pm ( - 64 ) ^{2} - 4 \cdot 16 ( - 64 )}{2 \cdot 16}

(- 64)^{2} - 4 \cdot 16 (- 64) = 642

t_{1, 2} = \frac{- ( - 64 ) \pm 64 2}{2 \cdot 16}

Separate the solutions

t_{1} = \frac{- ( - 64 ) + 64 2}{2 \cdot 16}, t_{2} = \frac{- ( - 64 ) - 64 2}{2 \cdot 16}

t = \frac{- ( - 64 ) + 64 2}{2 \cdot 16} : 2 (1 + 2)

t = \frac{- ( - 64 ) - 64 2}{2 \cdot 16} : 2 (1 - 2)

The solutions to the quadratic equation are:

t = 2 (1 + 2), t = 2 (1 - 2)

8 = - 4 + x

2 (3 y + 1) \leq - 10

2000 = - 0.1 x^{2} + 30 x

∣ 15 x + 9 ∣ - 5 = 1

0 = 3 x + 2

What are the solutions to the equation 16t^2-64t-64=0 ?
The solutions to the equation 16t^2-64t-64=0 are t=2(1+sqrt(2)),t=2(1-sqrt(2))
Find the zeros of 16t^2-64t-64=0
The zeros of 16t^2-64t-64=0 are t=2(1+sqrt(2)),t=2(1-sqrt(2))