What are the solutions to the equation 0=4x^2-x-3 ?

The solutions to the equation 0=4x^2-x-3 are x=1,x=-3/4

Find the zeros of 0=4x^2-x-3

The zeros of 0=4x^2-x-3 are x=1,x=-3/4

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0 = 4 x^{2} - x - 3

x = 1, x = - \frac{3}{4}

Decimal Notation

x = 1, x = - 0.75

Solution steps

0 = 4 x^{2} - x - 3

Switch sides

4 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 3) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 4}

x = \frac{- ( - 1 ) + 7}{2 \cdot 4} : 1

x = \frac{- ( - 1 ) - 7}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{4}

∣ 8 - 4 x ∣ = 5

x^{2} - 14 x + 15 = 0

7 (- 1 x + 3) = - 63

(\frac{X - 2}{X})^{2} \leq 6 (1 - \frac{2}{X}) - 8

- 8 b - 11 = - 9 b - 15

What are the solutions to the equation 0=4x^2-x-3 ?
The solutions to the equation 0=4x^2-x-3 are x=1,x=-3/4
Find the zeros of 0=4x^2-x-3
The zeros of 0=4x^2-x-3 are x=1,x=-3/4