erweitern (5(x^2(2x^2+3)-36))/(12x^4)

Lösung

erweitern

\frac{5 ( x ^{2} ( 2 x ^{2} + 3 ) - 36 )}{12 x ^{4}}

\frac{5}{6} + \frac{5}{4 x ^{2}} - \frac{15}{x ^{4}}

Schritte zur Lösung

\frac{5 ( x ^{2} ( 2 x ^{2} + 3 ) - 36 )}{12 x ^{4}}

Multipliziere aus

x^{2} (2 x^{2} + 3) - 36 : 2 x^{4} + 3 x^{2} - 36

= \frac{5 ( 2 x ^{4} + 3 x ^{2} - 36 )}{12 x ^{4}}

Multipliziere aus

5 (2 x^{4} + 3 x^{2} - 36) : 10 x^{4} + 15 x^{2} - 180

= \frac{10 x ^{4} + 15 x ^{2} - 180}{12 x ^{4}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 x ^{4} + 15 x ^{2} - 180}{12 x ^{4}} = \frac{10 x ^{4}}{12 x ^{4}} + \frac{15 x ^{2}}{12 x ^{4}} - \frac{180}{12 x ^{4}}

= \frac{10 x ^{4}}{12 x ^{4}} + \frac{15 x ^{2}}{12 x ^{4}} - \frac{180}{12 x ^{4}}

Streiche

\frac{10 x ^{4}}{12 x ^{4}} : \frac{5}{6}

= \frac{5}{6} + \frac{15 x ^{2}}{12 x ^{4}} - \frac{180}{12 x ^{4}}

Streiche

\frac{15 x ^{2}}{12 x ^{4}} : \frac{5}{4 x ^{2}}

= \frac{5}{6} + \frac{5}{4 x ^{2}} - \frac{180}{12 x ^{4}}

Teile die Zahlen:

\frac{180}{12} = 15

= \frac{5}{6} + \frac{5}{4 x ^{2}} - \frac{15}{x ^{4}}

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e x p an d \frac{4 y - 3 x}{2 ( 5 y ^{3} - 2 x )}

s im pl i f y 2 \cdot δ (x - 4) + 7 H (x - 11)

e x p an d \frac{( x - 1 ) ( 4 a ( x - 1 ) - 3 b )}{4 a + 3 b}

e x p an d ((t - 1)^{2}, t^{2} - 3 t + 2) \cdot (- 1, - 1)