展开 (4xy)/((x^2+1)(y^2+1))

解答

展开

\frac{4 x y}{( x ^{2} + 1 ) ( y ^{2} + 1 )}

\frac{4 x y}{x ^{2} y ^{2} + x ^{2} + y ^{2} + 1}

求解步骤

\frac{4 x y}{( x ^{2} + 1 ) ( y ^{2} + 1 )}

乘开

(x^{2} + 1) (y^{2} + 1) : x^{2} y^{2} + x^{2} + y^{2} + 1

= \frac{4 x y}{x ^{2} y ^{2} + x ^{2} + y ^{2} + 1}

e x p an d (1, 3) y (- 1, - 2)

e x p an d \frac{4 x ^{2}}{( 1 + x ^{2} ) ^{3}}

e x p an d \frac{2 ( x ^{2} - 1 )}{x ^{2} - 3}

e x p an d \frac{4 a x}{( x + a ) ^{2} ( x - a ) ^{2}}

e x p an d \frac{( x - 7 ) ^{2} ( m x - 7 m )}{( x - 7 ) ^{3} + ( m x - 7 m ) ^{2}}