erweitern ((2x+3)(3x+4))/6

Lösung

erweitern

\frac{( 2 x + 3 ) ( 3 x + 4 )}{6}

x^{2} + \frac{17 x}{6} + 2

Schritte zur Lösung

\frac{( 2 x + 3 ) ( 3 x + 4 )}{6}

Multipliziere aus

(2 x + 3) (3 x + 4) : 6 x^{2} + 17 x + 12

= \frac{6 x ^{2} + 17 x + 12}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 17 x + 12}{6} = \frac{6 x ^{2}}{6} + \frac{17 x}{6} + \frac{12}{6}

= \frac{6 x ^{2}}{6} + \frac{17 x}{6} + \frac{12}{6}

Teile die Zahlen:

\frac{6}{6} = 1

= x^{2} + \frac{17 x}{6} + \frac{12}{6}

Teile die Zahlen:

\frac{12}{6} = 2

= x^{2} + \frac{17 x}{6} + 2

e x p an d (1 + 3) i

e x p an d - \frac{- \frac{16}{5}}{t + 3} + \frac{\frac{11}{5}}{t - 2}

e x p an d \frac{n ( n + 1 ) ( n + 2 ) ( n + 3 )}{4}

e x p an d (e^{t} - 3)^{2}

e x p an d \frac{d}{d x} ((100 - 2 x) \cdot x) - x^{2}