展开 (0,0)y(2,-4)

解答

展开

(0, 0) y (2, - 4)

2 (0 \cdot 0,) y, - 4 (0 \cdot 0,) y

求解步骤

(0, 0) y (2, - 4)

= (0 \cdot 0,) (2, - 4) y

使用分配律:

a (b - c) = ab - a c

a = (0, 0) y, b = 2,, c = 4

= (0, 0) y \cdot 2, - (0, 0) y \cdot 4

= 2 (0 \cdot 0,) y, - 4 (0 \cdot 0,) y

e x p an d \frac{- 2 x ^{2} - 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

e x p an d (e^{x} + 1) (e^{- x} + 1)

e x p an d \frac{( x ^{2} + 1 - x ^{3} ) ( x ^{3} + 1 - x ^{2} )}{1 - x ^{2} - x ^{3}}

e x p an d (2 x + 3 y = 1, 8) - (3 x + 2 y = 21)

e x p an d - \frac{18}{( x + 1 ) ^{4}}