erweitern ((16x^2-1)(16x^2-1))/(64x^2)

Lösung

erweitern

\frac{( 16 x ^{2} - 1 ) ( 16 x ^{2} - 1 )}{64 x ^{2}}

4 x^{2} - \frac{1}{2} + \frac{1}{64 x ^{2}}

Schritte zur Lösung

\frac{( 16 x ^{2} - 1 ) ( 16 x ^{2} - 1 )}{64 x ^{2}}

(16 x^{2} - 1) (16 x^{2} - 1) = (16 x^{2} - 1)^{2}

= \frac{( 16 x ^{2} - 1 ) ^{2}}{64 x ^{2}}

(16 x^{2} - 1)^{2} = 256 x^{4} - 32 x^{2} + 1

= \frac{256 x ^{4} - 32 x ^{2} + 1}{64 x ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 x ^{4} - 32 x ^{2} + 1}{64 x ^{2}} = \frac{256 x ^{4}}{64 x ^{2}} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

= \frac{256 x ^{4}}{64 x ^{2}} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Streiche

\frac{256 x ^{4}}{64 x ^{2}} : 4 x^{2}

= 4 x^{2} - \frac{32 x ^{2}}{64 x ^{2}} + \frac{1}{64 x ^{2}}

Streiche

\frac{32 x ^{2}}{64 x ^{2}} : \frac{1}{2}

= 4 x^{2} - \frac{1}{2} + \frac{1}{64 x ^{2}}

e x p an d \frac{\partial}{\partial y} (4 e^{y}) + e^{y} (2 x + 4 y)

\frac{d}{d t} ((x) (2 sinh (t) + 3 t^{2}))

e x p an d \frac{( x ^{n + 1} - ( n + 1 ) x + n )}{x - 1}

e x p an d 6 sin (30 (t + 2))

e x p an d \frac{5 + x}{( x - 2 ) ^{2}}