解答
化简 (2+6i)3(34e1.0304i)4
解答
4.25284…+1.67139…i
求解步骤
(2+6i)3(34e1.0304i)4
(34e1.0304i)4=(34(cos(1.0304)+isin(1.0304)))4
=(2+6i)3(34(cos(1.0304)+isin(1.0304)))4
(2+6i)3=−208−144i
=(−208−144i)(34(cos(1.0304)+isin(1.0304)))4
(34(cos(1.0304)+sin(1.0304)i))4=342(0.51447…+0.85750…i)4
=(−208−144i)342(0.51447…+0.85750…i)4
去除括号: (−a)=−a=−208−144i342(0.51447…+0.85750…i)4
分解 −208−144i:−16(13+9i)
=−16(13+9i)342(0.51447…+0.85750…i)4
分解 342:22⋅172
分解 16:24
=−24(13+9i)22⋅172(0.51447…+0.85750…i)4
消掉 −24(13+9i)22⋅172(0.51447…+0.85750…i)4:−22(13+9i)172(0.51447…+0.85750…i)4
=−22(13+9i)172(0.51447…+0.85750…i)4
172=289=−22(13+9i)289(0.51447…+0.85750…i)4
22=4=−4(13+9i)289(0.51447…+0.85750…i)4
转换为小数形式4289=72.25=−72.25⋅(13+9i)(0.51447…+0.85750…i)4
去除括号: (a)=a=−72.25⋅13+9i(0.51447…+0.85750…i)4
分式相乘: a⋅cb=ca⋅b=−13+9i(0.51447…+0.85750…i)4⋅72.25
−13+9i72.25(0.51447…+0.85750…i)4有理化:−250−1063.21127…−417.84855…i
=−250−1063.21127…−417.84855…i
将 −250−1063.21127…−417.84855…i 改写成标准复数形式:4.25284…+1.67139…i
=4.25284…+1.67139…i