解答
展开 (2xx−1)(3−92x)8
解答
504x2−2448x+2x6561(x−1)−3224(x−1)x2+81560(x−1)x3−2187896(x−1)x4+59049896(x−1)x5−1594323512(x−1)x6+43046721128(x−1)x7+1944
求解步骤
(2xx−1)(3−92x)8
使用法则: (a)=a(2xx−1)=2xx−1=2xx−1(3−92x)8
展开 (3−92x)8:6561−3888x+1008x2−3448x3+811120x4−21871792x5+590491792x6−15943231024x7+43046721256x8
=2xx−1(6561−3888x+1008x2−3448x3+811120x4−21871792x5+590491792x6−15943231024x7+43046721256x8)
打开括号=2xx−1⋅6561+2xx−1(−3888x)+2xx−1⋅1008x2+2xx−1(−3448x3)+2xx−1⋅811120x4+2xx−1(−21871792x5)+2xx−1⋅590491792x6+2xx−1(−15943231024x7)+2xx−1⋅43046721256x8
化简 2xx−1⋅6561+2xx−1(−3888x)+2xx−1⋅1008x2+2xx−1(−3448x3)+2xx−1⋅811120x4+2xx−1(−21871792x5)+2xx−1⋅590491792x6+2xx−1(−15943231024x7)+2xx−1⋅43046721256x8:504x2−2448x+2x6561(x−1)−3224(x−1)x2+81560(x−1)x3−2187896(x−1)x4+59049896(x−1)x5−1594323512(x−1)x6+43046721128(x−1)x7+1944
=504x2−2448x+2x6561(x−1)−3224(x−1)x2+81560(x−1)x3−2187896(x−1)x4+59049896(x−1)x5−1594323512(x−1)x6+43046721128(x−1)x7+1944