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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x^2-19x+24=0 ?
- The solutions to the equation 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8
Find the zeros of 4x^2-19x+24=0
- The zeros of 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8