因式分解 28x^3+20x^2+14x+10

解答

因式分解

28 x^{3} + 20 x^{2} + 14 x + 10

2 (7 x + 5) (2 x^{2} + 1)

求解步骤

28 x^{3} + 20 x^{2} + 14 x + 10

因式分解出通项

2 : 2 (14 x^{3} + 10 x^{2} + 7 x + 5)

= 2 (14 x^{3} + 10 x^{2} + 7 x + 5)

因式分解

14 x^{3} + 10 x^{2} + 7 x + 5 : (7 x + 5) (2 x^{2} + 1)

= 2 (7 x + 5) (2 x^{2} + 1)

4.5 + 1.5 k = 18 - 3 k

3 x = 2 x + 6

f a c t or (5 x - 4)^{2} + 3 x (5 x - 4)

s im pl i f y 314

∣ x ∣ + 3 x > 1