What is the answer to 14x-(3x-2)-(5x+2-(x-1))=0 ?

The answer to 14x-(3x-2)-(5x+2-(x-1))=0 is x= 1/7

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14x-(3x-2)-(5x+2-(x-1))=0

14 x - (3 x - 2) - (5 x + 2 - (x - 1)) = 0

x = \frac{1}{7}

Solution steps

14 x - (3 x - 2) - (5 x + 2 - (x - 1)) = 0

Expand

14 x - (3 x - 2) - (5 x + 2 - (x - 1)) : 7 x - 1

7 x - 1 = 0

Move

1

to the right side

7 x = 1

Divide both sides by

7

x = \frac{1}{7}

24 x - 22 = 0

x, 4 x - 10 y = 40

x + \frac{3}{8} = \frac{1}{4}

v_{2}, F = \frac{m v _{2}}{t}

- 3 = 5

What is the answer to 14x-(3x-2)-(5x+2-(x-1))=0 ?
The answer to 14x-(3x-2)-(5x+2-(x-1))=0 is x= 1/7
Solve for x: 14x-(3x-2)-(5x+2-(x-1))=0
The solution is x= 1/7