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Frequently Asked Questions (FAQ)
What are the solutions to the equation (3x-5)^2=128 ?
- The solutions to the equation (3x-5)^2=128 are x=(8sqrt(2)+5)/3 ,x=(-8sqrt(2)+5)/3
Find the zeros of (3x-5)^2=128
- The zeros of (3x-5)^2=128 are x=(8sqrt(2)+5)/3 ,x=(-8sqrt(2)+5)/3